(2x^2+5x+5)(4x-3)=0

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Solution for (2x^2+5x+5)(4x-3)=0 equation: 


Simplifying
(2x2 + 5x + 5)(4x + -3) = 0

Reorder the terms:
(5 + 5x + 2x2)(4x + -3) = 0

Reorder the terms:
(5 + 5x + 2x2)(-3 + 4x) = 0

Multiply (5 + 5x + 2x2) * (-3 + 4x)
(5(-3 + 4x) + 5x * (-3 + 4x) + 2x2 * (-3 + 4x)) = 0
((-3 * 5 + 4x * 5) + 5x * (-3 + 4x) + 2x2 * (-3 + 4x)) = 0
((-15 + 20x) + 5x * (-3 + 4x) + 2x2 * (-3 + 4x)) = 0
(-15 + 20x + (-3 * 5x + 4x * 5x) + 2x2 * (-3 + 4x)) = 0
(-15 + 20x + (-15x + 20x2) + 2x2 * (-3 + 4x)) = 0
(-15 + 20x + -15x + 20x2 + (-3 * 2x2 + 4x * 2x2)) = 0
(-15 + 20x + -15x + 20x2 + (-6x2 + 8x3)) = 0

Combine like terms: 20x + -15x = 5x
(-15 + 5x + 20x2 + -6x2 + 8x3) = 0

Combine like terms: 20x2 + -6x2 = 14x2
(-15 + 5x + 14x2 + 8x3) = 0

Solving
-15 + 5x + 14x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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